What are the solutions to the equation 12b^2-27=0 ?

The solutions to the equation 12b^2-27=0 are b= 3/2 ,b=-3/2

Find the zeros of 12b^2-27=0

The zeros of 12b^2-27=0 are b= 3/2 ,b=-3/2

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12 b^{2} - 27 = 0

b = \frac{3}{2}, b = - \frac{3}{2}

Decimal Notation

b = 1.5, b = - 1.5

Solution steps

12 b^{2} - 27 = 0

Move

27

to the right side

12 b^{2} = 27

Divide both sides by

12

b^{2} = \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{9}{4}, b = - \frac{9}{4}

\frac{9}{4} = \frac{3}{2}

- \frac{9}{4} = - \frac{3}{2}

b = \frac{3}{2}, b = - \frac{3}{2}

x (x + 3) = - 2

3 x^{2} + 12 + 1 = 0

x^{2} + x - 56 = 0

- 144 + 7 x + x^{2} = 0

9 - \frac{x ^{2}}{3} = 0

What are the solutions to the equation 12b^2-27=0 ?
The solutions to the equation 12b^2-27=0 are b= 3/2 ,b=-3/2
Find the zeros of 12b^2-27=0
The zeros of 12b^2-27=0 are b= 3/2 ,b=-3/2