What are the solutions to the equation 4.9x^2-12x+5=0 ?

The solutions to the equation 4.9x^2-12x+5=0 are x=(5(12+sqrt(46)))/(49),x=(5(12-sqrt(46)))/(49)

Find the zeros of 4.9x^2-12x+5=0

The zeros of 4.9x^2-12x+5=0 are x=(5(12+sqrt(46)))/(49),x=(5(12-sqrt(46)))/(49)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4.9 x^{2} - 12 x + 5 = 0

x = \frac{5 ( 12 + 46 )}{49}, x = \frac{5 ( 12 - 46 )}{49}

Decimal Notation

x = 1.91656 \dots, x = 0.53241 \dots

Solution steps

4.9 x^{2} - 12 x + 5 = 0

Multiply both sides by

10

49 x^{2} - 120 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 120 ) \pm ( - 120 ) ^{2} - 4 \cdot 49 \cdot 50}{2 \cdot 49}

(- 120)^{2} - 4 \cdot 49 \cdot 50 = 1046

x_{1, 2} = \frac{- ( - 120 ) \pm 10 46}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 120 ) + 10 46}{2 \cdot 49}, x_{2} = \frac{- ( - 120 ) - 10 46}{2 \cdot 49}

x = \frac{- ( - 120 ) + 10 46}{2 \cdot 49} : \frac{5 ( 12 + 46 )}{49}

x = \frac{- ( - 120 ) - 10 46}{2 \cdot 49} : \frac{5 ( 12 - 46 )}{49}

The solutions to the quadratic equation are:

x = \frac{5 ( 12 + 46 )}{49}, x = \frac{5 ( 12 - 46 )}{49}

x^{2} = 5 \cdot 20

- 3 x^{2} + 12 x - 7 = 0

x^{2} - 2 x + 1 = 50

3 x^{2} + 114 = - 42 x

5 + 7 + 9 + (2 n + 3) = n (n + 4)

What are the solutions to the equation 4.9x^2-12x+5=0 ?
The solutions to the equation 4.9x^2-12x+5=0 are x=(5(12+sqrt(46)))/(49),x=(5(12-sqrt(46)))/(49)
Find the zeros of 4.9x^2-12x+5=0
The zeros of 4.9x^2-12x+5=0 are x=(5(12+sqrt(46)))/(49),x=(5(12-sqrt(46)))/(49)