What are the solutions to the equation 0.8x^2-8.16x+4.8=0 ?

The solutions to the equation 0.8x^2-8.16x+4.8=0 are x=(51+sqrt(2001))/(10),x=(51-sqrt(2001))/(10)

Find the zeros of 0.8x^2-8.16x+4.8=0

The zeros of 0.8x^2-8.16x+4.8=0 are x=(51+sqrt(2001))/(10),x=(51-sqrt(2001))/(10)

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0.8 x^{2} - 8.16 x + 4.8 = 0

x = \frac{51 + 2001}{10}, x = \frac{51 - 2001}{10}

Decimal Notation

x = 9.57325 \dots, x = 0.62674 \dots

Solution steps

0.8 x^{2} - 8.16 x + 4.8 = 0

Multiply both sides by

100

80 x^{2} - 816 x + 480 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 816 ) \pm ( - 816 ) ^{2} - 4 \cdot 80 \cdot 480}{2 \cdot 80}

(- 816)^{2} - 4 \cdot 80 \cdot 480 = 162001

x_{1, 2} = \frac{- ( - 816 ) \pm 16 2001}{2 \cdot 80}

Separate the solutions

x_{1} = \frac{- ( - 816 ) + 16 2001}{2 \cdot 80}, x_{2} = \frac{- ( - 816 ) - 16 2001}{2 \cdot 80}

x = \frac{- ( - 816 ) + 16 2001}{2 \cdot 80} : \frac{51 + 2001}{10}

x = \frac{- ( - 816 ) - 16 2001}{2 \cdot 80} : \frac{51 - 2001}{10}

The solutions to the quadratic equation are:

x = \frac{51 + 2001}{10}, x = \frac{51 - 2001}{10}

8 x^{2} - 2 x - 21 = 0

a, a^{5} + b^{5} = (a + b) (a^{4} - a^{3} b + a^{2} b^{2} - a b^{3} + b^{4})

q, \frac{1}{4} q^{2} + r = p

6 x^{2} + 17 x - 3 = 0

a^{2} + 1 3^{2} = 1 2^{2}

What are the solutions to the equation 0.8x^2-8.16x+4.8=0 ?
The solutions to the equation 0.8x^2-8.16x+4.8=0 are x=(51+sqrt(2001))/(10),x=(51-sqrt(2001))/(10)
Find the zeros of 0.8x^2-8.16x+4.8=0
The zeros of 0.8x^2-8.16x+4.8=0 are x=(51+sqrt(2001))/(10),x=(51-sqrt(2001))/(10)