What are the solutions to the equation c(x)=120x-40x^2 ?

The solutions to the equation c(x)=120x-40x^2 are x=0,x=(120-c)/(40)

Find the zeros of c(x)=120x-40x^2

The zeros of c(x)=120x-40x^2 are x=0,x=(120-c)/(40)

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c (x) = 120 x - 40 x^{2}

x = 0, x = \frac{120 - c}{40}

Solution steps

c (x) = 120 x - 40 x^{2}

Refine

c x = 120 x - 40 x^{2}

Switch sides

120 x - 40 x^{2} = c x

Move

c x

to the left side

120 x - 40 x^{2} - c x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 40 x^{2} + (120 - c) x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 120 - c ) \pm ( 120 - c ) ^{2} - 4 ( - 40 ) \cdot 0}{2 ( - 40 )}

Simplify

(120 - c)^{2} - 4 (- 40) \cdot 0 : - c + 120

x_{1, 2} = \frac{- ( 120 - c ) \pm ( - c + 120 )}{2 ( - 40 )}

Separate the solutions

x_{1} = \frac{- ( 120 - c ) - c + 120}{2 ( - 40 )}, x_{2} = \frac{- ( 120 - c ) - ( - c + 120 )}{2 ( - 40 )}

x = \frac{- ( 120 - c ) - c + 120}{2 ( - 40 )} : 0

x = \frac{- ( 120 - c ) - ( - c + 120 )}{2 ( - 40 )} : \frac{120 - c}{40}

The solutions to the quadratic equation are:

x = 0, x = \frac{120 - c}{40}

x^{2} + 4 x - 9

x^{2} + 4 x - 8

- x^{2} + 72 x = - 216 - 7 x^{2}

- 5 x^{2} + x + 4 = 0

n^{2} + 7 n + 6 = 0

What are the solutions to the equation c(x)=120x-40x^2 ?
The solutions to the equation c(x)=120x-40x^2 are x=0,x=(120-c)/(40)
Find the zeros of c(x)=120x-40x^2
The zeros of c(x)=120x-40x^2 are x=0,x=(120-c)/(40)