What are the solutions to the equation quadraticformula x^2-2x+5=0 ?

The solutions to the equation quadraticformula x^2-2x+5=0 are x=1+2i,x=1-2i

Find the zeros of quadraticformula x^2-2x+5=0

The zeros of quadraticformula x^2-2x+5=0 are x=1+2i,x=1-2i

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x^{2} - 2 x + 5 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

x^{2} - 2 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 5 : 4 i

x_{1, 2} = \frac{- ( - 2 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 i}{2 \cdot 1} : 1 + 2 i

x = \frac{- ( - 2 ) - 4 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

x, - x^{2} y + 3 + y^{3} = 0

3 x - 4 = - 2 x^{2}

\frac{1}{9000} x^{2} - \frac{7}{15} x + 500

x^{2} + 10 x = 0

100 x^{2} + 20 x + 1 = 0

What are the solutions to the equation quadraticformula x^2-2x+5=0 ?
The solutions to the equation quadraticformula x^2-2x+5=0 are x=1+2i,x=1-2i
Find the zeros of quadraticformula x^2-2x+5=0
The zeros of quadraticformula x^2-2x+5=0 are x=1+2i,x=1-2i