What are the solutions to the equation 4x^2+20x-24=0 ?

The solutions to the equation 4x^2+20x-24=0 are x=1,x=-6

Find the zeros of 4x^2+20x-24=0

The zeros of 4x^2+20x-24=0 are x=1,x=-6

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4 x^{2} + 20 x - 24 = 0

x = 1, x = - 6

Solution steps

4 x^{2} + 20 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 ( - 24 )}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 (- 24) = 28

x_{1, 2} = \frac{- 20 \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 28}{2 \cdot 4}, x_{2} = \frac{- 20 - 28}{2 \cdot 4}

x = \frac{- 20 + 28}{2 \cdot 4} : 1

x = \frac{- 20 - 28}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

x = 1, x = - 6

\frac{1}{5} + \frac{1}{10}

\frac{21}{6}

3 x - p y - 3 y + p x

2 x^{2} + 64 = - 24 x

\frac{53000}{4 \cdot π \cdot 240 0 ^{2}} \cdot 100

What are the solutions to the equation 4x^2+20x-24=0 ?
The solutions to the equation 4x^2+20x-24=0 are x=1,x=-6
Find the zeros of 4x^2+20x-24=0
The zeros of 4x^2+20x-24=0 are x=1,x=-6