What are the solutions to the equation 2x^2+64=-24x ?

The solutions to the equation 2x^2+64=-24x are x=-4,x=-8

Find the zeros of 2x^2+64=-24x

The zeros of 2x^2+64=-24x are x=-4,x=-8

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2 x^{2} + 64 = - 24 x

x = - 4, x = - 8

Solution steps

2 x^{2} + 64 = - 24 x

Move

24 x

to the left side

2 x^{2} + 64 + 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 24 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 2 \cdot 64}{2 \cdot 2}

2 4^{2} - 4 \cdot 2 \cdot 64 = 8

x_{1, 2} = \frac{- 24 \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 24 + 8}{2 \cdot 2}, x_{2} = \frac{- 24 - 8}{2 \cdot 2}

x = \frac{- 24 + 8}{2 \cdot 2} : - 4

x = \frac{- 24 - 8}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = - 4, x = - 8

\frac{53000}{4 \cdot π \cdot 240 0 ^{2}} \cdot 100

x^{2} - 4 x = 3

∣ 2 x + 5 ∣ - 1 < 0

2 ∣ 2 x - 1 ∣ - 8 = 18

\frac{8 x ^{7} y}{40 x ^{8} y ^{6}}

What are the solutions to the equation 2x^2+64=-24x ?
The solutions to the equation 2x^2+64=-24x are x=-4,x=-8
Find the zeros of 2x^2+64=-24x
The zeros of 2x^2+64=-24x are x=-4,x=-8