What are the solutions to the equation completesquare-2z^2+56z=10 ?

The solutions to the equation completesquare-2z^2+56z=10 are z=sqrt(191)+14,z=-sqrt(191)+14

Find the zeros of completesquare-2z^2+56z=10

The zeros of completesquare-2z^2+56z=10 are z=sqrt(191)+14,z=-sqrt(191)+14

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- 2 z^{2} + 56 z = 10

z = 191 + 14, z = - 191 + 14

Decimal Notation

z = 27.82027 \dots, z = 0.17972 \dots

Solution steps

- 2 z^{2} + 56 z = 10

Divide both sides by

- 2

\frac{- 2 z ^{2} + 56 z}{- 2} = \frac{10}{- 2}

z^{2} - 28 z = - 5

Rewrite in the form

(x + a)^{2} = b

(z - 14)^{2} = 191

For

the solutions are

f (x) = a, - a

Solve

z - 14 = 191 : z = 191 + 14

Solve

z - 14 = - 191 : z = - 191 + 14

The solutions to the quadratic equation are:

z = 191 + 14, z = - 191 + 14

a^{2} + a - 1 = 0

x^{2} + 9 x^{2} + 20 = 0

x, x^{2} + 4 x + 9 = 0

x^{2} = \frac{16}{9}

y, x^{4} + x^{3} y = 4 y^{2} x + y

What are the solutions to the equation completesquare-2z^2+56z=10 ?
The solutions to the equation completesquare-2z^2+56z=10 are z=sqrt(191)+14,z=-sqrt(191)+14
Find the zeros of completesquare-2z^2+56z=10
The zeros of completesquare-2z^2+56z=10 are z=sqrt(191)+14,z=-sqrt(191)+14