What are the solutions to the equation 3t^2-7t=1 ?

The solutions to the equation 3t^2-7t=1 are t=(7+sqrt(61))/6 ,t=(7-sqrt(61))/6

Find the zeros of 3t^2-7t=1

The zeros of 3t^2-7t=1 are t=(7+sqrt(61))/6 ,t=(7-sqrt(61))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 t^{2} - 7 t = 1

t = \frac{7 + 61}{6}, t = \frac{7 - 61}{6}

Decimal Notation

t = 2.46837 \dots, t = - 0.13504 \dots

Solution steps

3 t^{2} - 7 t = 1

Move

1

to the left side

3 t^{2} - 7 t - 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 (- 1) = 61

t_{1, 2} = \frac{- ( - 7 ) \pm 61}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 7 ) + 61}{2 \cdot 3}, t_{2} = \frac{- ( - 7 ) - 61}{2 \cdot 3}

t = \frac{- ( - 7 ) + 61}{2 \cdot 3} : \frac{7 + 61}{6}

t = \frac{- ( - 7 ) - 61}{2 \cdot 3} : \frac{7 - 61}{6}

The solutions to the quadratic equation are:

t = \frac{7 + 61}{6}, t = \frac{7 - 61}{6}

q^{2} - 16 = 0

- 4 x^{2} - 48 x - 20 = 0

r^{2} + 4 r - 4 = 0

4 x^{2} + 9

x^{2} - 40 x + 404 = 0

What are the solutions to the equation 3t^2-7t=1 ?
The solutions to the equation 3t^2-7t=1 are t=(7+sqrt(61))/6 ,t=(7-sqrt(61))/6
Find the zeros of 3t^2-7t=1
The zeros of 3t^2-7t=1 are t=(7+sqrt(61))/6 ,t=(7-sqrt(61))/6