What are the solutions to the equation completesquare-4x^2-48x-20=0 ?

The solutions to the equation completesquare-4x^2-48x-20=0 are x=sqrt(31)-6,x=-sqrt(31)-6

Find the zeros of completesquare-4x^2-48x-20=0

The zeros of completesquare-4x^2-48x-20=0 are x=sqrt(31)-6,x=-sqrt(31)-6

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- 4 x^{2} - 48 x - 20 = 0

x = 31 - 6, x = - 31 - 6

Decimal Notation

x = - 0.43223 \dots, x = - 11.56776 \dots

Solution steps

- 4 x^{2} - 48 x - 20 = 0

Move

20

to the right side

- 4 x^{2} - 48 x = 20

Divide both sides by

- 4

\frac{- 4 x ^{2} - 48 x}{- 4} = \frac{20}{- 4}

x^{2} + 12 x = - 5

Rewrite in the form

(x + a)^{2} = b

(x + 6)^{2} = 31

For

the solutions are

f (x) = a, - a

Solve

x + 6 = 31 : x = 31 - 6

Solve

x + 6 = - 31 : x = - 31 - 6

The solutions to the quadratic equation are:

x = 31 - 6, x = - 31 - 6

r^{2} + 4 r - 4 = 0

4 x^{2} + 9

x^{2} - 40 x + 404 = 0

- 4 x^{2} + 6 x - 25 = 0

5 x^{2} + 4 x - 28 = 0

What are the solutions to the equation completesquare-4x^2-48x-20=0 ?
The solutions to the equation completesquare-4x^2-48x-20=0 are x=sqrt(31)-6,x=-sqrt(31)-6
Find the zeros of completesquare-4x^2-48x-20=0
The zeros of completesquare-4x^2-48x-20=0 are x=sqrt(31)-6,x=-sqrt(31)-6