What are the solutions to the equation x^2=24-4x ?

The solutions to the equation x^2=24-4x are x=2(sqrt(7)-1),x=-2(1+sqrt(7))

Find the zeros of x^2=24-4x

The zeros of x^2=24-4x are x=2(sqrt(7)-1),x=-2(1+sqrt(7))

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x^{2} = 24 - 4 x

x = 2 (7 - 1), x = - 2 (1 + 7)

Decimal Notation

x = 3.29150 \dots, x = - 7.29150 \dots

Solution steps

x^{2} = 24 - 4 x

Move

4 x

to the left side

x^{2} + 4 x = 24

Move

24

to the left side

x^{2} + 4 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 24) = 47

x_{1, 2} = \frac{- 4 \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 7}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 7}{2 \cdot 1}

x = \frac{- 4 + 4 7}{2 \cdot 1} : 2 (7 - 1)

x = \frac{- 4 - 4 7}{2 \cdot 1} : - 2 (1 + 7)

The solutions to the quadratic equation are:

x = 2 (7 - 1), x = - 2 (1 + 7)

(x - 12) (x - 6) = 27

- 16 t^{2} + 80 t + 60 = 0

- \frac{x ^{2}}{200} + x - 2 = 39

- 5 (x + 1) (x - 3) = 0

y, 2 x y - y^{2} = 1

What are the solutions to the equation x^2=24-4x ?
The solutions to the equation x^2=24-4x are x=2(sqrt(7)-1),x=-2(1+sqrt(7))
Find the zeros of x^2=24-4x
The zeros of x^2=24-4x are x=2(sqrt(7)-1),x=-2(1+sqrt(7))