What are the solutions to the equation z^2-6z-27=0 ?

The solutions to the equation z^2-6z-27=0 are z=9,z=-3

Find the zeros of z^2-6z-27=0

The zeros of z^2-6z-27=0 are z=9,z=-3

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z^{2} - 6 z - 27 = 0

z = 9, z = - 3

Solution steps

z^{2} - 6 z - 27 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 27) = 12

z_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 1}, z_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 1}

z = \frac{- ( - 6 ) + 12}{2 \cdot 1} : 9

z = \frac{- ( - 6 ) - 12}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

z = 9, z = - 3

\frac{x}{9} + \frac{1}{3} = \frac{1}{8}

x^{2} + 20 x = - 225

9 x + 4 < 2 x + 4

12 x^{3} + 2 x^{2} + 6 x

\frac{1}{3} n \geq 9

What are the solutions to the equation z^2-6z-27=0 ?
The solutions to the equation z^2-6z-27=0 are z=9,z=-3
Find the zeros of z^2-6z-27=0
The zeros of z^2-6z-27=0 are z=9,z=-3