What are the solutions to the equation (4-m)^2-4(3)(3m-36)=0 ?

The solutions to the equation (4-m)^2-4(3)(3m-36)=0 are m=28,m=16

Find the zeros of (4-m)^2-4(3)(3m-36)=0

The zeros of (4-m)^2-4(3)(3m-36)=0 are m=28,m=16

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(4 - m)^{2} - 4 (3) (3 m - 36) = 0

m = 28, m = 16

Solution steps

(4 - m)^{2} - 4 (3) (3 m - 36) = 0

Expand

(4 - m)^{2} - 4 (3) (3 m - 36) : m^{2} - 44 m + 448

m^{2} - 44 m + 448 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 44 ) \pm ( - 44 ) ^{2} - 4 \cdot 1 \cdot 448}{2 \cdot 1}

(- 44)^{2} - 4 \cdot 1 \cdot 448 = 12

m_{1, 2} = \frac{- ( - 44 ) \pm 12}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 44 ) + 12}{2 \cdot 1}, m_{2} = \frac{- ( - 44 ) - 12}{2 \cdot 1}

m = \frac{- ( - 44 ) + 12}{2 \cdot 1} : 28

m = \frac{- ( - 44 ) - 12}{2 \cdot 1} : 16

The solutions to the quadratic equation are:

m = 28, m = 16

x (2 x - 3) = 9

2 x^{2} - 12 x + 23 = 0

x^{2} + 16 x + 8 = 0

(x - 10)^{2} + 10 = 100

4 x^{2} - 6 x = 6 x

What are the solutions to the equation (4-m)^2-4(3)(3m-36)=0 ?
The solutions to the equation (4-m)^2-4(3)(3m-36)=0 are m=28,m=16
Find the zeros of (4-m)^2-4(3)(3m-36)=0
The zeros of (4-m)^2-4(3)(3m-36)=0 are m=28,m=16