What are the solutions to the equation x(2x-3)=9 ?

The solutions to the equation x(2x-3)=9 are x=3,x=-3/2

Find the zeros of x(2x-3)=9

The zeros of x(2x-3)=9 are x=3,x=-3/2

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x (2 x - 3) = 9

x = 3, x = - \frac{3}{2}

Decimal Notation

x = 3, x = - 1.5

Solution steps

x (2 x - 3) = 9

Expand

x (2 x - 3) : 2 x^{2} - 3 x

2 x^{2} - 3 x = 9

Move

9

to the left side

2 x^{2} - 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 9) = 9

x_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 2}

x = \frac{- ( - 3 ) + 9}{2 \cdot 2} : 3

x = \frac{- ( - 3 ) - 9}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{3}{2}

2 x^{2} - 12 x + 23 = 0

x^{2} + 16 x + 8 = 0

(x - 10)^{2} + 10 = 100

4 x^{2} - 6 x = 6 x

- 5 x^{2} + x - 4 = 0

What are the solutions to the equation x(2x-3)=9 ?
The solutions to the equation x(2x-3)=9 are x=3,x=-3/2
Find the zeros of x(2x-3)=9
The zeros of x(2x-3)=9 are x=3,x=-3/2