What are the solutions to the equation -5x^2+x-4=0 ?

The solutions to the equation -5x^2+x-4=0 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)

Find the zeros of -5x^2+x-4=0

The zeros of -5x^2+x-4=0 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)

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- 5 x^{2} + x - 4 = 0

x = \frac{1}{10} - i \frac{79}{10}, x = \frac{1}{10} + i \frac{79}{10}

Solution steps

- 5 x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 5 ) ( - 4 )}{2 ( - 5 )}

Simplify

1^{2} - 4 (- 5) (- 4) : 79 i

x_{1, 2} = \frac{- 1 \pm 79 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1 + 79 i}{2 ( - 5 )}, x_{2} = \frac{- 1 - 79 i}{2 ( - 5 )}

x = \frac{- 1 + 79 i}{2 ( - 5 )} : \frac{1}{10} - i \frac{79}{10}

x = \frac{- 1 - 79 i}{2 ( - 5 )} : \frac{1}{10} + i \frac{79}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10} - i \frac{79}{10}, x = \frac{1}{10} + i \frac{79}{10}

m^{2} + 49 = 0

x^{2} - x + \frac{2}{9} = 0

9 x^{2} - 12 x + 10 = 0

2 y^{2} - 7 y + 6 = 0

x^{2} + 6 x = 5 + 3

What are the solutions to the equation -5x^2+x-4=0 ?
The solutions to the equation -5x^2+x-4=0 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)
Find the zeros of -5x^2+x-4=0
The zeros of -5x^2+x-4=0 are x= 1/10-i(sqrt(79))/(10),x= 1/10+i(sqrt(79))/(10)