What are the solutions to the equation 18x^2-66x+42=0 ?

The solutions to the equation 18x^2-66x+42=0 are x=(11+sqrt(37))/6 ,x=(11-sqrt(37))/6

Find the zeros of 18x^2-66x+42=0

The zeros of 18x^2-66x+42=0 are x=(11+sqrt(37))/6 ,x=(11-sqrt(37))/6

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18 x^{2} - 66 x + 42 = 0

x = \frac{11 + 37}{6}, x = \frac{11 - 37}{6}

Decimal Notation

x = 2.84712 \dots, x = 0.81953 \dots

Solution steps

18 x^{2} - 66 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 66 ) \pm ( - 66 ) ^{2} - 4 \cdot 18 \cdot 42}{2 \cdot 18}

(- 66)^{2} - 4 \cdot 18 \cdot 42 = 637

x_{1, 2} = \frac{- ( - 66 ) \pm 6 37}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 66 ) + 6 37}{2 \cdot 18}, x_{2} = \frac{- ( - 66 ) - 6 37}{2 \cdot 18}

x = \frac{- ( - 66 ) + 6 37}{2 \cdot 18} : \frac{11 + 37}{6}

x = \frac{- ( - 66 ) - 6 37}{2 \cdot 18} : \frac{11 - 37}{6}

The solutions to the quadratic equation are:

x = \frac{11 + 37}{6}, x = \frac{11 - 37}{6}

2 x - x^{2} = 3

3 x^{2} = 363

2 x^{2} = - 9 x + 3

6 = \frac{V ^{2}}{2 ( \frac{20}{3} )}

x^{2} + 16 x + 4 = 0

What are the solutions to the equation 18x^2-66x+42=0 ?
The solutions to the equation 18x^2-66x+42=0 are x=(11+sqrt(37))/6 ,x=(11-sqrt(37))/6
Find the zeros of 18x^2-66x+42=0
The zeros of 18x^2-66x+42=0 are x=(11+sqrt(37))/6 ,x=(11-sqrt(37))/6