What are the solutions to the equation c^2-13c-14=0 ?

The solutions to the equation c^2-13c-14=0 are c=14,c=-1

Find the zeros of c^2-13c-14=0

The zeros of c^2-13c-14=0 are c=14,c=-1

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c^{2} - 13 c - 14 = 0

c = 14, c = - 1

Solution steps

c^{2} - 13 c - 14 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 14) = 15

c_{1, 2} = \frac{- ( - 13 ) \pm 15}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 13 ) + 15}{2 \cdot 1}, c_{2} = \frac{- ( - 13 ) - 15}{2 \cdot 1}

c = \frac{- ( - 13 ) + 15}{2 \cdot 1} : 14

c = \frac{- ( - 13 ) - 15}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

c = 14, c = - 1

4 x^{2} - x - 4 = 0

x^{2} + 6 x + 6 = 0

a^{2} + 1^{2} = 3^{2}

x, 3 x^{2} + 2 x y - 4 y = 0

25 = y^{2}

What are the solutions to the equation c^2-13c-14=0 ?
The solutions to the equation c^2-13c-14=0 are c=14,c=-1
Find the zeros of c^2-13c-14=0
The zeros of c^2-13c-14=0 are c=14,c=-1