What are the solutions to the equation a^2+1^2=3^2 ?

The solutions to the equation a^2+1^2=3^2 are a=2sqrt(2),a=-2sqrt(2)

Find the zeros of a^2+1^2=3^2

The zeros of a^2+1^2=3^2 are a=2sqrt(2),a=-2sqrt(2)

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a^{2} + 1^{2} = 3^{2}

a = 22, a = - 22

Decimal Notation

a = 2.82842 \dots, a = - 2.82842 \dots

Solution steps

a^{2} + 1^{2} = 3^{2}

Move

1^{2}

to the right side

a^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 8, a = - 8

8 = 22

- 8 = - 22

a = 22, a = - 22

x, 3 x^{2} + 2 x y - 4 y = 0

25 = y^{2}

(x + 3)^{2} + 1 0^{2} = 2 6^{2}

6 q^{2} - 150 q + 600 = 0

x, x^{2} - 14 x + 49 = 0

What are the solutions to the equation a^2+1^2=3^2 ?
The solutions to the equation a^2+1^2=3^2 are a=2sqrt(2),a=-2sqrt(2)
Find the zeros of a^2+1^2=3^2
The zeros of a^2+1^2=3^2 are a=2sqrt(2),a=-2sqrt(2)