What are the solutions to the equation 8+2m^2=32 ?

The solutions to the equation 8+2m^2=32 are m=2sqrt(3),m=-2sqrt(3)

Find the zeros of 8+2m^2=32

The zeros of 8+2m^2=32 are m=2sqrt(3),m=-2sqrt(3)

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8 + 2 m^{2} = 32

m = 23, m = - 23

Decimal Notation

m = 3.46410 \dots, m = - 3.46410 \dots

Solution steps

8 + 2 m^{2} = 32

Move

8

to the right side

2 m^{2} = 24

Divide both sides by

2

m^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 12, m = - 12

12 = 23

- 12 = - 23

m = 23, m = - 23

t^{2} - 8 t = 0

13 - 6 x = (2 x - 5)^{2} + 3

x, - \frac{1}{y} = x - 4 x^{2}

0 = - 4.9 t^{2} + 4.25 t + 100

m^{2} + 17 m + 72 = 0

What are the solutions to the equation 8+2m^2=32 ?
The solutions to the equation 8+2m^2=32 are m=2sqrt(3),m=-2sqrt(3)
Find the zeros of 8+2m^2=32
The zeros of 8+2m^2=32 are m=2sqrt(3),m=-2sqrt(3)