What are the solutions to the equation 2x^2-x=7 ?

The solutions to the equation 2x^2-x=7 are x=(1+sqrt(57))/4 ,x=(1-sqrt(57))/4

Find the zeros of 2x^2-x=7

The zeros of 2x^2-x=7 are x=(1+sqrt(57))/4 ,x=(1-sqrt(57))/4

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2 x^{2} - x = 7

x = \frac{1 + 57}{4}, x = \frac{1 - 57}{4}

Decimal Notation

x = 2.13745 \dots, x = - 1.63745 \dots

Solution steps

2 x^{2} - x = 7

Move

7

to the left side

2 x^{2} - x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 7) = 57

x_{1, 2} = \frac{- ( - 1 ) \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 57}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 57}{2 \cdot 2}

x = \frac{- ( - 1 ) + 57}{2 \cdot 2} : \frac{1 + 57}{4}

x = \frac{- ( - 1 ) - 57}{2 \cdot 2} : \frac{1 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 57}{4}, x = \frac{1 - 57}{4}

x^{2} - 36 = - 9 - 2 x^{2}

\frac{x ^{2} + 2}{3} - \frac{x ^{2} + 1}{4} = 1 - \frac{x + 7}{12}

r (r + 2) = 99

x^{2} + 200 x + 10000 = 0

3 x^{2} + 12 x - 10 = - 3

What are the solutions to the equation 2x^2-x=7 ?
The solutions to the equation 2x^2-x=7 are x=(1+sqrt(57))/4 ,x=(1-sqrt(57))/4
Find the zeros of 2x^2-x=7
The zeros of 2x^2-x=7 are x=(1+sqrt(57))/4 ,x=(1-sqrt(57))/4