What are the solutions to the equation 3x^2+12x-10=-3 ?

The solutions to the equation 3x^2+12x-10=-3 are x=(-6+sqrt(57))/3 ,x=-(6+sqrt(57))/3

Find the zeros of 3x^2+12x-10=-3

The zeros of 3x^2+12x-10=-3 are x=(-6+sqrt(57))/3 ,x=-(6+sqrt(57))/3

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3 x^{2} + 12 x - 10 = - 3

x = \frac{- 6 + 57}{3}, x = - \frac{6 + 57}{3}

Decimal Notation

x = 0.51661 \dots, x = - 4.51661 \dots

Solution steps

3 x^{2} + 12 x - 10 = - 3

Move

3

to the left side

3 x^{2} + 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 7) = 257

x_{1, 2} = \frac{- 12 \pm 2 57}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 57}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 57}{2 \cdot 3}

x = \frac{- 12 + 2 57}{2 \cdot 3} : \frac{- 6 + 57}{3}

x = \frac{- 12 - 2 57}{2 \cdot 3} : - \frac{6 + 57}{3}

The solutions to the quadratic equation are:

x = \frac{- 6 + 57}{3}, x = - \frac{6 + 57}{3}

\frac{1}{5} x^{2} + \frac{2}{5} x + 2 = 0

3 x^{(2)} + 13 = - 12 x

x^{2} + 12 x + 20 = 0

m x^{2} - (m^{2} + 5 m - 5) x + 5 m - 9 = x^{2}

0 = - 16 t^{2} + 900

What are the solutions to the equation 3x^2+12x-10=-3 ?
The solutions to the equation 3x^2+12x-10=-3 are x=(-6+sqrt(57))/3 ,x=-(6+sqrt(57))/3
Find the zeros of 3x^2+12x-10=-3
The zeros of 3x^2+12x-10=-3 are x=(-6+sqrt(57))/3 ,x=-(6+sqrt(57))/3