What are the solutions to the equation 1/5 x^2+2/5 x+2=0 ?

The solutions to the equation 1/5 x^2+2/5 x+2=0 are x=-1+3i,x=-1-3i

Find the zeros of 1/5 x^2+2/5 x+2=0

The zeros of 1/5 x^2+2/5 x+2=0 are x=-1+3i,x=-1-3i

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\frac{1}{5} x^{2} + \frac{2}{5} x + 2 = 0

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

\frac{1}{5} x^{2} + \frac{2}{5} x + 2 = 0

Multiply both sides by

5

x^{2} + 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 10 : 6 i

x_{1, 2} = \frac{- 2 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 6 i}{2 \cdot 1}

x = \frac{- 2 + 6 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 6 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

3 x^{(2)} + 13 = - 12 x

x^{2} + 12 x + 20 = 0

m x^{2} - (m^{2} + 5 m - 5) x + 5 m - 9 = x^{2}

0 = - 16 t^{2} + 900

4 s^{2} - 100 = 0

What are the solutions to the equation 1/5 x^2+2/5 x+2=0 ?
The solutions to the equation 1/5 x^2+2/5 x+2=0 are x=-1+3i,x=-1-3i
Find the zeros of 1/5 x^2+2/5 x+2=0
The zeros of 1/5 x^2+2/5 x+2=0 are x=-1+3i,x=-1-3i