What are the solutions to the equation 3x^{(2)}+13=-12x ?

The solutions to the equation 3x^{(2)}+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3

Find the zeros of 3x^{(2)}+13=-12x

The zeros of 3x^{(2)}+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3

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3 x^{(2)} + 13 = - 12 x

x = - 2 + i \frac{3}{3}, x = - 2 - i \frac{3}{3}

Solution steps

3 x^{(2)} + 13 = - 12 x

Refine

3 x^{2} + 13 = - 12 x

Move

12 x

to the left side

3 x^{2} + 13 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 12 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 13}{2 \cdot 3}

Simplify

1 2^{2} - 4 \cdot 3 \cdot 13 : 23 i

x_{1, 2} = \frac{- 12 \pm 2 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 3 i}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 3 i}{2 \cdot 3}

x = \frac{- 12 + 2 3 i}{2 \cdot 3} : - 2 + i \frac{3}{3}

x = \frac{- 12 - 2 3 i}{2 \cdot 3} : - 2 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - 2 + i \frac{3}{3}, x = - 2 - i \frac{3}{3}

x^{2} + 12 x + 20 = 0

m x^{2} - (m^{2} + 5 m - 5) x + 5 m - 9 = x^{2}

0 = - 16 t^{2} + 900

4 s^{2} - 100 = 0

8 x^{2} + 12 x = - 1

What are the solutions to the equation 3x^{(2)}+13=-12x ?
The solutions to the equation 3x^{(2)}+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3
Find the zeros of 3x^{(2)}+13=-12x
The zeros of 3x^{(2)}+13=-12x are x=-2+i(sqrt(3))/3 ,x=-2-i(sqrt(3))/3