What are the solutions to the equation 8x^2+12x=-1 ?

The solutions to the equation 8x^2+12x=-1 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4

Find the zeros of 8x^2+12x=-1

The zeros of 8x^2+12x=-1 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4

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8 x^{2} + 12 x = - 1

x = \frac{- 3 + 7}{4}, x = - \frac{3 + 7}{4}

Decimal Notation

x = - 0.08856 \dots, x = - 1.41143 \dots

Solution steps

8 x^{2} + 12 x = - 1

Move

1

to the left side

8 x^{2} + 12 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

1 2^{2} - 4 \cdot 8 \cdot 1 = 47

x_{1, 2} = \frac{- 12 \pm 4 7}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 12 + 4 7}{2 \cdot 8}, x_{2} = \frac{- 12 - 4 7}{2 \cdot 8}

x = \frac{- 12 + 4 7}{2 \cdot 8} : \frac{- 3 + 7}{4}

x = \frac{- 12 - 4 7}{2 \cdot 8} : - \frac{3 + 7}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 7}{4}, x = - \frac{3 + 7}{4}

- 4.9 t^{2} + 28 t = 0

18 x^{2} - 792 x + 6534 = 0

4 x^{2} + 28 x + 49

4 x^{1} + 2 x^{2} = 60

x^{2} + 10 x + 33 = 0

What are the solutions to the equation 8x^2+12x=-1 ?
The solutions to the equation 8x^2+12x=-1 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4
Find the zeros of 8x^2+12x=-1
The zeros of 8x^2+12x=-1 are x=(-3+sqrt(7))/4 ,x=-(3+sqrt(7))/4