What are the solutions to the equation 18x^2-792x+6534=0 ?

The solutions to the equation 18x^2-792x+6534=0 are x=33,x=11

Find the zeros of 18x^2-792x+6534=0

The zeros of 18x^2-792x+6534=0 are x=33,x=11

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18 x^{2} - 792 x + 6534 = 0

x = 33, x = 11

Solution steps

18 x^{2} - 792 x + 6534 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 792 ) \pm ( - 792 ) ^{2} - 4 \cdot 18 \cdot 6534}{2 \cdot 18}

(- 792)^{2} - 4 \cdot 18 \cdot 6534 = 396

x_{1, 2} = \frac{- ( - 792 ) \pm 396}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- ( - 792 ) + 396}{2 \cdot 18}, x_{2} = \frac{- ( - 792 ) - 396}{2 \cdot 18}

x = \frac{- ( - 792 ) + 396}{2 \cdot 18} : 33

x = \frac{- ( - 792 ) - 396}{2 \cdot 18} : 11

The solutions to the quadratic equation are:

x = 33, x = 11

4 x^{2} + 28 x + 49

4 x^{1} + 2 x^{2} = 60

x^{2} + 10 x + 33 = 0

x (x + 5) - 3 = 2 x (x - 6)

15 x^{2} = 40 (x + 2)

What are the solutions to the equation 18x^2-792x+6534=0 ?
The solutions to the equation 18x^2-792x+6534=0 are x=33,x=11
Find the zeros of 18x^2-792x+6534=0
The zeros of 18x^2-792x+6534=0 are x=33,x=11