What are the solutions to the equation 4x^1+2x^2=60 ?

The solutions to the equation 4x^1+2x^2=60 are x=-1+sqrt(31),x=-1-sqrt(31)

Find the zeros of 4x^1+2x^2=60

The zeros of 4x^1+2x^2=60 are x=-1+sqrt(31),x=-1-sqrt(31)

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4 x^{1} + 2 x^{2} = 60

x = - 1 + 31, x = - 1 - 31

Decimal Notation

x = 4.56776 \dots, x = - 6.56776 \dots

Solution steps

4 x^{1} + 2 x^{2} = 60

Refine

4 x + 2 x^{2} = 60

Move

60

to the left side

4 x + 2 x^{2} - 60 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 4 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

4^{2} - 4 \cdot 2 (- 60) = 431

x_{1, 2} = \frac{- 4 \pm 4 31}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 4 + 4 31}{2 \cdot 2}, x_{2} = \frac{- 4 - 4 31}{2 \cdot 2}

x = \frac{- 4 + 4 31}{2 \cdot 2} : - 1 + 31

x = \frac{- 4 - 4 31}{2 \cdot 2} : - 1 - 31

The solutions to the quadratic equation are:

x = - 1 + 31, x = - 1 - 31

x^{2} + 10 x + 33 = 0

x (x + 5) - 3 = 2 x (x - 6)

15 x^{2} = 40 (x + 2)

12 x = 13 - x^{2}

6 k^{2} + 12 k - 15 = - 10

What are the solutions to the equation 4x^1+2x^2=60 ?
The solutions to the equation 4x^1+2x^2=60 are x=-1+sqrt(31),x=-1-sqrt(31)
Find the zeros of 4x^1+2x^2=60
The zeros of 4x^1+2x^2=60 are x=-1+sqrt(31),x=-1-sqrt(31)