What are the solutions to the equation 6k^2+12k-15=-10 ?

The solutions to the equation 6k^2+12k-15=-10 are k=(-6+sqrt(66))/6 ,k=-(6+sqrt(66))/6

Find the zeros of 6k^2+12k-15=-10

The zeros of 6k^2+12k-15=-10 are k=(-6+sqrt(66))/6 ,k=-(6+sqrt(66))/6

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6 k^{2} + 12 k - 15 = - 10

k = \frac{- 6 + 66}{6}, k = - \frac{6 + 66}{6}

Decimal Notation

k = 0.35400 \dots, k = - 2.35400 \dots

Solution steps

6 k^{2} + 12 k - 15 = - 10

Move

10

to the left side

6 k^{2} + 12 k - 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 5) = 266

k_{1, 2} = \frac{- 12 \pm 2 66}{2 \cdot 6}

Separate the solutions

k_{1} = \frac{- 12 + 2 66}{2 \cdot 6}, k_{2} = \frac{- 12 - 2 66}{2 \cdot 6}

k = \frac{- 12 + 2 66}{2 \cdot 6} : \frac{- 6 + 66}{6}

k = \frac{- 12 - 2 66}{2 \cdot 6} : - \frac{6 + 66}{6}

The solutions to the quadratic equation are:

k = \frac{- 6 + 66}{6}, k = - \frac{6 + 66}{6}

x, x^{2} = k y^{3}

(x + 6)^{2} = 40

18 x^{2} - 720 x + 5400 = 0

a, a^{2} + b^{2} = 2 a - 6 b - 10

12 x^{2} - x - 13 = 0

What are the solutions to the equation 6k^2+12k-15=-10 ?
The solutions to the equation 6k^2+12k-15=-10 are k=(-6+sqrt(66))/6 ,k=-(6+sqrt(66))/6
Find the zeros of 6k^2+12k-15=-10
The zeros of 6k^2+12k-15=-10 are k=(-6+sqrt(66))/6 ,k=-(6+sqrt(66))/6