What are the solutions to the equation (x+1)^2+(x-2)^2=15 ?

The solutions to the equation (x+1)^2+(x-2)^2=15 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2

Find the zeros of (x+1)^2+(x-2)^2=15

The zeros of (x+1)^2+(x-2)^2=15 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2

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(x + 1)^{2} + (x - 2)^{2} = 15

x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

Decimal

x = 2.79128 \dots, x = - 1.79128 \dots

Solution steps

(x + 1)^{2} + (x - 2)^{2} = 15

Expand

(x + 1)^{2} + (x - 2)^{2} : 2 x^{2} - 2 x + 5

2 x^{2} - 2 x + 5 = 15

Move

15

to the left side

2 x^{2} - 2 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 10) = 221

x_{1, 2} = \frac{- ( - 2 ) \pm 2 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 21}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 2 21}{2 \cdot 2}

x = \frac{- ( - 2 ) + 2 21}{2 \cdot 2} : \frac{1 + 21}{2}

x = \frac{- ( - 2 ) - 2 21}{2 \cdot 2} : \frac{1 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

- 8 x^{2} - 3 x - 2 = - 10 x^{2}

x (x + 1) = 360

x, x^{2} y + y = x + 1

4 (x + 3)^{2} = 32

t^{2} - 10 t + 9 = 0

What are the solutions to the equation (x+1)^2+(x-2)^2=15 ?
The solutions to the equation (x+1)^2+(x-2)^2=15 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2
Find the zeros of (x+1)^2+(x-2)^2=15
The zeros of (x+1)^2+(x-2)^2=15 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2