What are the solutions to the equation x^2-19x+23=0 ?

The solutions to the equation x^2-19x+23=0 are x=(19+sqrt(269))/2 ,x=(19-sqrt(269))/2

Find the zeros of x^2-19x+23=0

The zeros of x^2-19x+23=0 are x=(19+sqrt(269))/2 ,x=(19-sqrt(269))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 19 x + 23 = 0

x = \frac{19 + 269}{2}, x = \frac{19 - 269}{2}

Decimal Notation

x = 17.70060 \dots, x = 1.29939 \dots

Solution steps

x^{2} - 19 x + 23 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 23 = 269

x_{1, 2} = \frac{- ( - 19 ) \pm 269}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 269}{2 \cdot 1}, x_{2} = \frac{- ( - 19 ) - 269}{2 \cdot 1}

x = \frac{- ( - 19 ) + 269}{2 \cdot 1} : \frac{19 + 269}{2}

x = \frac{- ( - 19 ) - 269}{2 \cdot 1} : \frac{19 - 269}{2}

The solutions to the quadratic equation are:

x = \frac{19 + 269}{2}, x = \frac{19 - 269}{2}

y^{2} = 4 y + 12

x^{2} + 12 x - 4

t, d = - 3 t^{2} + 12 t - 7

x^{2} - 2 x + 7 = 3

x^{2} + 12 x + 4

What are the solutions to the equation x^2-19x+23=0 ?
The solutions to the equation x^2-19x+23=0 are x=(19+sqrt(269))/2 ,x=(19-sqrt(269))/2
Find the zeros of x^2-19x+23=0
The zeros of x^2-19x+23=0 are x=(19+sqrt(269))/2 ,x=(19-sqrt(269))/2