What are the solutions to the equation 4x^2+24x+13=2x^2+6x ?

The solutions to the equation 4x^2+24x+13=2x^2+6x are x=(-9+sqrt(55))/2 ,x=-(9+sqrt(55))/2

Find the zeros of 4x^2+24x+13=2x^2+6x

The zeros of 4x^2+24x+13=2x^2+6x are x=(-9+sqrt(55))/2 ,x=-(9+sqrt(55))/2

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4 x^{2} + 24 x + 13 = 2 x^{2} + 6 x

x = \frac{- 9 + 55}{2}, x = - \frac{9 + 55}{2}

Decimal Notation

x = - 0.79190 \dots, x = - 8.20809 \dots

Solution steps

4 x^{2} + 24 x + 13 = 2 x^{2} + 6 x

Move

6 x

to the left side

4 x^{2} + 18 x + 13 = 2 x^{2}

Move

2 x^{2}

to the left side

2 x^{2} + 18 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 2 \cdot 13}{2 \cdot 2}

1 8^{2} - 4 \cdot 2 \cdot 13 = 255

x_{1, 2} = \frac{- 18 \pm 2 55}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 18 + 2 55}{2 \cdot 2}, x_{2} = \frac{- 18 - 2 55}{2 \cdot 2}

x = \frac{- 18 + 2 55}{2 \cdot 2} : \frac{- 9 + 55}{2}

x = \frac{- 18 - 2 55}{2 \cdot 2} : - \frac{9 + 55}{2}

The solutions to the quadratic equation are:

x = \frac{- 9 + 55}{2}, x = - \frac{9 + 55}{2}

x^{2} + 8 x - 35 = 0

x^{2} + 15 x + 64 = 0

(x - 5)^{2} = 2

12 x^{2} + 12 x - 72 = 0

40 x - x^{2} = 0

What are the solutions to the equation 4x^2+24x+13=2x^2+6x ?
The solutions to the equation 4x^2+24x+13=2x^2+6x are x=(-9+sqrt(55))/2 ,x=-(9+sqrt(55))/2
Find the zeros of 4x^2+24x+13=2x^2+6x
The zeros of 4x^2+24x+13=2x^2+6x are x=(-9+sqrt(55))/2 ,x=-(9+sqrt(55))/2