What are the solutions to the equation 2x^2-8x-18=0 ?

The solutions to the equation 2x^2-8x-18=0 are x=2+sqrt(13),x=2-sqrt(13)

Find the zeros of 2x^2-8x-18=0

The zeros of 2x^2-8x-18=0 are x=2+sqrt(13),x=2-sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 8 x - 18 = 0

x = 2 + 13, x = 2 - 13

Decimal Notation

x = 5.60555 \dots, x = - 1.60555 \dots

Solution steps

2 x^{2} - 8 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 (- 18) = 413

x_{1, 2} = \frac{- ( - 8 ) \pm 4 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 13}{2 \cdot 2}, x_{2} = \frac{- ( - 8 ) - 4 13}{2 \cdot 2}

x = \frac{- ( - 8 ) + 4 13}{2 \cdot 2} : 2 + 13

x = \frac{- ( - 8 ) - 4 13}{2 \cdot 2} : 2 - 13

The solutions to the quadratic equation are:

x = 2 + 13, x = 2 - 13

18 x^{2} - 45 x = 0

3 n^{2} - 8 n - 26 = 9

x, x^{2} + y^{2} = a^{2}

x^{2} - 4 x - 7 x + (x - 1)^{2} = 7 + 8 - 3 x

2 n^{2} + 6 n - 4 = 0

What are the solutions to the equation 2x^2-8x-18=0 ?
The solutions to the equation 2x^2-8x-18=0 are x=2+sqrt(13),x=2-sqrt(13)
Find the zeros of 2x^2-8x-18=0
The zeros of 2x^2-8x-18=0 are x=2+sqrt(13),x=2-sqrt(13)