What are the solutions to the equation 2n^2+6n-4=0 ?

The solutions to the equation 2n^2+6n-4=0 are n=(-3+sqrt(17))/2 ,n=-(3+sqrt(17))/2

Find the zeros of 2n^2+6n-4=0

The zeros of 2n^2+6n-4=0 are n=(-3+sqrt(17))/2 ,n=-(3+sqrt(17))/2

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2 n^{2} + 6 n - 4 = 0

n = \frac{- 3 + 17}{2}, n = - \frac{3 + 17}{2}

Decimal Notation

n = 0.56155 \dots, n = - 3.56155 \dots

Solution steps

2 n^{2} + 6 n - 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 4) = 217

n_{1, 2} = \frac{- 6 \pm 2 17}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- 6 + 2 17}{2 \cdot 2}, n_{2} = \frac{- 6 - 2 17}{2 \cdot 2}

n = \frac{- 6 + 2 17}{2 \cdot 2} : \frac{- 3 + 17}{2}

n = \frac{- 6 - 2 17}{2 \cdot 2} : - \frac{3 + 17}{2}

The solutions to the quadratic equation are:

n = \frac{- 3 + 17}{2}, n = - \frac{3 + 17}{2}

x, y^{3} - 9 y^{2} + 15 y = x^{2} + 10 x - 8

(x - 6)^{2} = 5

x^{2} - 1 - 1 = 0

r, y = 2 (x + r)^{2} - s

2 x^{2} = 5 x + 5

What are the solutions to the equation 2n^2+6n-4=0 ?
The solutions to the equation 2n^2+6n-4=0 are n=(-3+sqrt(17))/2 ,n=-(3+sqrt(17))/2
Find the zeros of 2n^2+6n-4=0
The zeros of 2n^2+6n-4=0 are n=(-3+sqrt(17))/2 ,n=-(3+sqrt(17))/2