What are the solutions to the equation v^2-2v-8=0 ?

The solutions to the equation v^2-2v-8=0 are v=4,v=-2

Find the zeros of v^2-2v-8=0

The zeros of v^2-2v-8=0 are v=4,v=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v^{2} - 2 v - 8 = 0

v = 4, v = - 2

Solution steps

v^{2} - 2 v - 8 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

v_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, v_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

v = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

v = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

v = 4, v = - 2

4 x^{2} + 8 x = - 2

- x^{2} + 2 x + 3 = 0

4 y^{2} = 0

2 x^{2} - 3 x = - 8

3 (x^{2} - 1) = 9

What are the solutions to the equation v^2-2v-8=0 ?
The solutions to the equation v^2-2v-8=0 are v=4,v=-2
Find the zeros of v^2-2v-8=0
The zeros of v^2-2v-8=0 are v=4,v=-2