What are the solutions to the equation 4x^2+64x+240=0 ?

The solutions to the equation 4x^2+64x+240=0 are x=-6,x=-10

Find the zeros of 4x^2+64x+240=0

The zeros of 4x^2+64x+240=0 are x=-6,x=-10

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4 x^{2} + 64 x + 240 = 0

x = - 6, x = - 10

Solution steps

4 x^{2} + 64 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 4 \cdot 240}{2 \cdot 4}

6 4^{2} - 4 \cdot 4 \cdot 240 = 16

x_{1, 2} = \frac{- 64 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 64 + 16}{2 \cdot 4}, x_{2} = \frac{- 64 - 16}{2 \cdot 4}

x = \frac{- 64 + 16}{2 \cdot 4} : - 6

x = \frac{- 64 - 16}{2 \cdot 4} : - 10

The solutions to the quadratic equation are:

x = - 6, x = - 10

7 x^{2} - 2 x - 32 = 0

x, x^{2} + y x - x + y + 4 = 0

p^{2} - p - 12 = 0

10 n^{2} - n - 8 = 0

s, f = {\frac{1 - 2 s ^{2}}{- x + 2}}

What are the solutions to the equation 4x^2+64x+240=0 ?
The solutions to the equation 4x^2+64x+240=0 are x=-6,x=-10
Find the zeros of 4x^2+64x+240=0
The zeros of 4x^2+64x+240=0 are x=-6,x=-10