What are the solutions to the equation solvefor x,x^2+y^2-18x+81=0 ?

The solutions to the equation solvefor x,x^2+y^2-18x+81=0 are x=9+iy,x=9-iy

Find the zeros of solvefor x,x^2+y^2-18x+81=0

The zeros of solvefor x,x^2+y^2-18x+81=0 are x=9+iy,x=9-iy

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solve for

x, x^{2} + y^{2} - 18 x + 81 = 0

x = 9 + i y, x = 9 - i y

Solution steps

x^{2} + y^{2} - 18 x + 81 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 18 x + y^{2} + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} + 81 )}{2 \cdot 1}

Simplify

(- 18)^{2} - 4 \cdot 1 \cdot (y^{2} + 81) : 2 i y

x_{1, 2} = \frac{- ( - 18 ) \pm 2 i y}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 i y}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 i y}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 i y}{2 \cdot 1} : 9 + i y

x = \frac{- ( - 18 ) - 2 i y}{2 \cdot 1} : 9 - i y

The solutions to the quadratic equation are:

x = 9 + i y, x = 9 - i y

X^{2} - 7 X + 12 = 0

- 9 n^{2} + 2 n + 21 = - 5 n^{2}

4 x^{2} + 6 x = 0

- 8 + x^{2} = 0

x^{2} + 4 x - 8 = 0

What are the solutions to the equation solvefor x,x^2+y^2-18x+81=0 ?
The solutions to the equation solvefor x,x^2+y^2-18x+81=0 are x=9+iy,x=9-iy
Find the zeros of solvefor x,x^2+y^2-18x+81=0
The zeros of solvefor x,x^2+y^2-18x+81=0 are x=9+iy,x=9-iy