What are the solutions to the equation (k+2)^2=12 ?

The solutions to the equation (k+2)^2=12 are k=2sqrt(3)-2,k=-2sqrt(3)-2

Find the zeros of (k+2)^2=12

The zeros of (k+2)^2=12 are k=2sqrt(3)-2,k=-2sqrt(3)-2

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(k + 2)^{2} = 12

k = 23 - 2, k = - 23 - 2

Decimal Notation

k = 1.46410 \dots, k = - 5.46410 \dots

Solution steps

(k + 2)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + 2 = 12 : k = 23 - 2

Solve

k + 2 = - 12 : k = - 23 - 2

The solutions to the quadratic equation are:

k = 23 - 2, k = - 23 - 2

x + 5 = x^{2} - 2 x + 1

v^{2} + 8 v + 1 = 0

x^{2} - 5 x + 31 = 0

- 0.5 x^{2} + 40 x - 300 = 300

3 x^{2} + 12 x = 15

What are the solutions to the equation (k+2)^2=12 ?
The solutions to the equation (k+2)^2=12 are k=2sqrt(3)-2,k=-2sqrt(3)-2
Find the zeros of (k+2)^2=12
The zeros of (k+2)^2=12 are k=2sqrt(3)-2,k=-2sqrt(3)-2