What are the solutions to the equation 4(x^2-5)-9=7 ?

The solutions to the equation 4(x^2-5)-9=7 are x=3,x=-3

Find the zeros of 4(x^2-5)-9=7

The zeros of 4(x^2-5)-9=7 are x=3,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 (x^{2} - 5) - 9 = 7

x = 3, x = - 3

Solution steps

4 (x^{2} - 5) - 9 = 7

Move

9

to the right side

4 (x^{2} - 5) = 16

Divide both sides by

4

x^{2} - 5 = 4

Move

5

to the right side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

b^{2} - 9 b + 8 = 0

5 + \frac{5}{8} + \frac{5}{8} + \frac{5}{8} + \frac{5}{8} - 0.625

x^{2} + 11 x + 28

2 a^{2} - 3 a + 1

- 2 (\frac{2}{5})^{- 1}

What are the solutions to the equation 4(x^2-5)-9=7 ?
The solutions to the equation 4(x^2-5)-9=7 are x=3,x=-3
Find the zeros of 4(x^2-5)-9=7
The zeros of 4(x^2-5)-9=7 are x=3,x=-3