What are the solutions to the equation 7x^2-1=-2x ?

The solutions to the equation 7x^2-1=-2x are x=(-1+2sqrt(2))/7 ,x=-(1+2sqrt(2))/7

Find the zeros of 7x^2-1=-2x

The zeros of 7x^2-1=-2x are x=(-1+2sqrt(2))/7 ,x=-(1+2sqrt(2))/7

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7 x^{2} - 1 = - 2 x

x = \frac{- 1 + 2 2}{7}, x = - \frac{1 + 2 2}{7}

Decimal Notation

x = 0.26120 \dots, x = - 0.54691 \dots

Solution steps

7 x^{2} - 1 = - 2 x

Move

2 x

to the left side

7 x^{2} - 1 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

2^{2} - 4 \cdot 7 (- 1) = 42

x_{1, 2} = \frac{- 2 \pm 4 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 2 + 4 2}{2 \cdot 7}, x_{2} = \frac{- 2 - 4 2}{2 \cdot 7}

x = \frac{- 2 + 4 2}{2 \cdot 7} : \frac{- 1 + 2 2}{7}

x = \frac{- 2 - 4 2}{2 \cdot 7} : - \frac{1 + 2 2}{7}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 2}{7}, x = - \frac{1 + 2 2}{7}

x, x^{2} - 25 = 0

4 x^{2} + 4 x + 26

0 = x^{2} - 6 x - 5

4 z^{2} - 3 z - 3 = 0

0 = x^{2} - 12 x + 27

What are the solutions to the equation 7x^2-1=-2x ?
The solutions to the equation 7x^2-1=-2x are x=(-1+2sqrt(2))/7 ,x=-(1+2sqrt(2))/7
Find the zeros of 7x^2-1=-2x
The zeros of 7x^2-1=-2x are x=(-1+2sqrt(2))/7 ,x=-(1+2sqrt(2))/7