What are the solutions to the equation 1/2 x^2+8x+32=0 ?

The solutions to the equation 1/2 x^2+8x+32=0 are x=-8

Find the zeros of 1/2 x^2+8x+32=0

The zeros of 1/2 x^2+8x+32=0 are x=-8

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\frac{1}{2} x^{2} + 8 x + 32 = 0

x = - 8

Solution steps

\frac{1}{2} x^{2} + 8 x + 32 = 0

Multiply both sides by

2

x^{2} + 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- 16 \pm 0}{2 \cdot 1}

x = \frac{- 16}{2 \cdot 1}

\frac{- 16}{2 \cdot 1} = - 8

x = - 8

The solution to the quadratic equation is:

x = - 8

- 3 x^{2} - 30 x - 54 = 0

7 x^{2} - 21 x - 196 = 0

- 7 x = 3 x^{2} - 1

- 4 b = b^{2} - 21

b^{2} + 11 = 92

What are the solutions to the equation 1/2 x^2+8x+32=0 ?
The solutions to the equation 1/2 x^2+8x+32=0 are x=-8
Find the zeros of 1/2 x^2+8x+32=0
The zeros of 1/2 x^2+8x+32=0 are x=-8