What are the solutions to the equation b^2+11=92 ?

The solutions to the equation b^2+11=92 are b=9,b=-9

Find the zeros of b^2+11=92

The zeros of b^2+11=92 are b=9,b=-9

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b^{2} + 11 = 92

b = 9, b = - 9

Solution steps

b^{2} + 11 = 92

Move

11

to the right side

b^{2} = 81

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 81, b = - 81

81 = 9

- 81 = - 9

b = 9, b = - 9

0 = - 0.1 x^{2} - 0.2 x + 8

9 x^{2} + 9 x - 2 = 0

x^{2} + 13 x + 31 = 0

- 16 t^{2} + 96 t + 432 = 0

0 = 6 x^{2} + x - 5

What are the solutions to the equation b^2+11=92 ?
The solutions to the equation b^2+11=92 are b=9,b=-9
Find the zeros of b^2+11=92
The zeros of b^2+11=92 are b=9,b=-9