What are the solutions to the equation -16t^2+96t+432=0 ?

The solutions to the equation -16t^2+96t+432=0 are t=-3,t=9

Find the zeros of -16t^2+96t+432=0

The zeros of -16t^2+96t+432=0 are t=-3,t=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 16 t^{2} + 96 t + 432 = 0

t = - 3, t = 9

Solution steps

- 16 t^{2} + 96 t + 432 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 432}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 432 = 192

t_{1, 2} = \frac{- 96 \pm 192}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 192}{2 ( - 16 )}, t_{2} = \frac{- 96 - 192}{2 ( - 16 )}

t = \frac{- 96 + 192}{2 ( - 16 )} : - 3

t = \frac{- 96 - 192}{2 ( - 16 )} : 9

The solutions to the quadratic equation are:

t = - 3, t = 9

0 = 6 x^{2} + x - 5

128 = 96 t - 16 t^{2}

(2 k + 3)^{2} - 19 = 81

100 + x^{2} = 220 + 2 x

x^{2} - 6 x + 9 = 0

What are the solutions to the equation -16t^2+96t+432=0 ?
The solutions to the equation -16t^2+96t+432=0 are t=-3,t=9
Find the zeros of -16t^2+96t+432=0
The zeros of -16t^2+96t+432=0 are t=-3,t=9