What are the solutions to the equation 5x^2+8=-12x ?

The solutions to the equation 5x^2+8=-12x are x=-6/5+i 2/5 ,x=-6/5-i 2/5

Find the zeros of 5x^2+8=-12x

The zeros of 5x^2+8=-12x are x=-6/5+i 2/5 ,x=-6/5-i 2/5

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5 x^{2} + 8 = - 12 x

x = - \frac{6}{5} + i \frac{2}{5}, x = - \frac{6}{5} - i \frac{2}{5}

Solution steps

5 x^{2} + 8 = - 12 x

Move

12 x

to the left side

5 x^{2} + 8 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} + 12 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

1 2^{2} - 4 \cdot 5 \cdot 8 : 4 i

x_{1, 2} = \frac{- 12 \pm 4 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 12 + 4 i}{2 \cdot 5}, x_{2} = \frac{- 12 - 4 i}{2 \cdot 5}

x = \frac{- 12 + 4 i}{2 \cdot 5} : - \frac{6}{5} + i \frac{2}{5}

x = \frac{- 12 - 4 i}{2 \cdot 5} : - \frac{6}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = - \frac{6}{5} + i \frac{2}{5}, x = - \frac{6}{5} - i \frac{2}{5}

4 X^{2} - 8 X + 3 = 0

6 x^{2} - 5 x + 7 = 0

x, 3 x^{2} - 2 x - 1 = 0

λ^{2} - λ + 1 = 0

12 x^{2} - 60 x + 5

What are the solutions to the equation 5x^2+8=-12x ?
The solutions to the equation 5x^2+8=-12x are x=-6/5+i 2/5 ,x=-6/5-i 2/5
Find the zeros of 5x^2+8=-12x
The zeros of 5x^2+8=-12x are x=-6/5+i 2/5 ,x=-6/5-i 2/5