What are the solutions to the equation -a^2-a+6=0 ?

The solutions to the equation -a^2-a+6=0 are a=-3,a=2

Find the zeros of -a^2-a+6=0

The zeros of -a^2-a+6=0 are a=-3,a=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- a^{2} - a + 6 = 0

a = - 3, a = 2

Solution steps

- a^{2} - a + 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 6 = 5

a_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, a_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

a = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - 3

a = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

a = - 3, a = 2

2 x^{2} + 5 x = x - 4

h^{2} = 3^{2} + 4^{2}

n^{2} - 10 n = - 21

- 5 x^{2} + 40 x - 76 = 4

2 x^{2} + 4 x - 576 = 0

What are the solutions to the equation -a^2-a+6=0 ?
The solutions to the equation -a^2-a+6=0 are a=-3,a=2
Find the zeros of -a^2-a+6=0
The zeros of -a^2-a+6=0 are a=-3,a=2