What are the solutions to the equation 2x^2-x-6=-3x-2 ?

The solutions to the equation 2x^2-x-6=-3x-2 are x=1,x=-2

Find the zeros of 2x^2-x-6=-3x-2

The zeros of 2x^2-x-6=-3x-2 are x=1,x=-2

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2 x^{2} - x - 6 = - 3 x - 2

x = 1, x = - 2

Solution steps

2 x^{2} - x - 6 = - 3 x - 2

Move

2

to the left side

2 x^{2} - x - 4 = - 3 x

Move

3 x

to the left side

2 x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 4) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 2}, x_{2} = \frac{- 2 - 6}{2 \cdot 2}

x = \frac{- 2 + 6}{2 \cdot 2} : 1

x = \frac{- 2 - 6}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

4 - x^{2}

3 x^{2} + 10 x - 6 = 0

- x^{2} + 6 x + 4

15 x^{2} - x = 2

- 2 x^{2} - 7 = 0

What are the solutions to the equation 2x^2-x-6=-3x-2 ?
The solutions to the equation 2x^2-x-6=-3x-2 are x=1,x=-2
Find the zeros of 2x^2-x-6=-3x-2
The zeros of 2x^2-x-6=-3x-2 are x=1,x=-2