What are the solutions to the equation 5x^2-9x+8=0 ?

The solutions to the equation 5x^2-9x+8=0 are x= 9/10+i(sqrt(79))/(10),x= 9/10-i(sqrt(79))/(10)

Find the zeros of 5x^2-9x+8=0

The zeros of 5x^2-9x+8=0 are x= 9/10+i(sqrt(79))/(10),x= 9/10-i(sqrt(79))/(10)

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5 x^{2} - 9 x + 8 = 0

x = \frac{9}{10} + i \frac{79}{10}, x = \frac{9}{10} - i \frac{79}{10}

Solution steps

5 x^{2} - 9 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 \cdot 8}{2 \cdot 5}

Simplify

(- 9)^{2} - 4 \cdot 5 \cdot 8 : 79 i

x_{1, 2} = \frac{- ( - 9 ) \pm 79 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 79 i}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 79 i}{2 \cdot 5}

x = \frac{- ( - 9 ) + 79 i}{2 \cdot 5} : \frac{9}{10} + i \frac{79}{10}

x = \frac{- ( - 9 ) - 79 i}{2 \cdot 5} : \frac{9}{10} - i \frac{79}{10}

The solutions to the quadratic equation are:

x = \frac{9}{10} + i \frac{79}{10}, x = \frac{9}{10} - i \frac{79}{10}

(20 + x) (30 + x) = 1690

x^{2} + 3 x + 3 = 10

x (x + 2)^{2} = (x + 1)^{3} + 5

x^{2} + 2 x + 4 = 0

x, (x - 1)^{2} + (y - 2)^{2} = 0

What are the solutions to the equation 5x^2-9x+8=0 ?
The solutions to the equation 5x^2-9x+8=0 are x= 9/10+i(sqrt(79))/(10),x= 9/10-i(sqrt(79))/(10)
Find the zeros of 5x^2-9x+8=0
The zeros of 5x^2-9x+8=0 are x= 9/10+i(sqrt(79))/(10),x= 9/10-i(sqrt(79))/(10)