What are the solutions to the equation 10v^2-20v+10=0 ?

The solutions to the equation 10v^2-20v+10=0 are v=1

Find the zeros of 10v^2-20v+10=0

The zeros of 10v^2-20v+10=0 are v=1

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10 v^{2} - 20 v + 10 = 0

v = 1

Solution steps

10 v^{2} - 20 v + 10 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 20)^{2} - 4 \cdot 10 \cdot 10 = 0

v_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 10}

v = \frac{- ( - 20 )}{2 \cdot 10}

\frac{- ( - 20 )}{2 \cdot 10} = 1

v = 1

The solution to the quadratic equation is:

v = 1

30 x^{2} - 10 = 5 x^{2} - 1

m^{2} - 2 m - 2 = 0

x, x^{2} + y^{2} - 2 x - 2 y + 2 = 0

m^{2} - 7 m + 12 = 0

10 x^{2} + 19 x + 6 = 0

What are the solutions to the equation 10v^2-20v+10=0 ?
The solutions to the equation 10v^2-20v+10=0 are v=1
Find the zeros of 10v^2-20v+10=0
The zeros of 10v^2-20v+10=0 are v=1