What are the solutions to the equation m^2-2m-2=0 ?

The solutions to the equation m^2-2m-2=0 are m=1+sqrt(3),m=1-sqrt(3)

Find the zeros of m^2-2m-2=0

The zeros of m^2-2m-2=0 are m=1+sqrt(3),m=1-sqrt(3)

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m^{2} - 2 m - 2 = 0

m = 1 + 3, m = 1 - 3

Decimal Notation

m = 2.73205 \dots, m = - 0.73205 \dots

Solution steps

m^{2} - 2 m - 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 2) = 23

m_{1, 2} = \frac{- ( - 2 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 3}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 3}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 3}{2 \cdot 1} : 1 + 3

m = \frac{- ( - 2 ) - 2 3}{2 \cdot 1} : 1 - 3

The solutions to the quadratic equation are:

m = 1 + 3, m = 1 - 3

x, x^{2} + y^{2} - 2 x - 2 y + 2 = 0

m^{2} - 7 m + 12 = 0

10 x^{2} + 19 x + 6 = 0

2 x^{2} + 20 x - 150 = 0

9^{2} + x^{2} = 1 3^{2}

What are the solutions to the equation m^2-2m-2=0 ?
The solutions to the equation m^2-2m-2=0 are m=1+sqrt(3),m=1-sqrt(3)
Find the zeros of m^2-2m-2=0
The zeros of m^2-2m-2=0 are m=1+sqrt(3),m=1-sqrt(3)