What are the solutions to the equation 2x^2+20x-150=0 ?

The solutions to the equation 2x^2+20x-150=0 are x=5,x=-15

Find the zeros of 2x^2+20x-150=0

The zeros of 2x^2+20x-150=0 are x=5,x=-15

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2 x^{2} + 20 x - 150 = 0

x = 5, x = - 15

Solution steps

2 x^{2} + 20 x - 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 150 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 150) = 40

x_{1, 2} = \frac{- 20 \pm 40}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 40}{2 \cdot 2}, x_{2} = \frac{- 20 - 40}{2 \cdot 2}

x = \frac{- 20 + 40}{2 \cdot 2} : 5

x = \frac{- 20 - 40}{2 \cdot 2} : - 15

The solutions to the quadratic equation are:

x = 5, x = - 15

9^{2} + x^{2} = 1 3^{2}

\frac{1}{7} x^{2} + 2 x + 7 = 0

r^{2} + r - 56 = 0

r^{2} = - 36

24 (x + 4) (x + 3) - 24 (x + 2) (x + 5) = (x + 5) (x + 3)

What are the solutions to the equation 2x^2+20x-150=0 ?
The solutions to the equation 2x^2+20x-150=0 are x=5,x=-15
Find the zeros of 2x^2+20x-150=0
The zeros of 2x^2+20x-150=0 are x=5,x=-15