What are the solutions to the equation x^2-13x+5=0 ?

The solutions to the equation x^2-13x+5=0 are x=(13+sqrt(149))/2 ,x=(13-sqrt(149))/2

Find the zeros of x^2-13x+5=0

The zeros of x^2-13x+5=0 are x=(13+sqrt(149))/2 ,x=(13-sqrt(149))/2

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x^{2} - 13 x + 5 = 0

x = \frac{13 + 149}{2}, x = \frac{13 - 149}{2}

Decimal Notation

x = 12.60327 \dots, x = 0.39672 \dots

Solution steps

x^{2} - 13 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 5 = 149

x_{1, 2} = \frac{- ( - 13 ) \pm 149}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 149}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 149}{2 \cdot 1}

x = \frac{- ( - 13 ) + 149}{2 \cdot 1} : \frac{13 + 149}{2}

x = \frac{- ( - 13 ) - 149}{2 \cdot 1} : \frac{13 - 149}{2}

The solutions to the quadratic equation are:

x = \frac{13 + 149}{2}, x = \frac{13 - 149}{2}

q, 3 + q^{2} = \frac{G}{R}

- x^{2} + 121 = 0

10 x^{2} - 5 = - 20

p^{2} - 1 = 0

x^{2} + 8 x + 13 = 0

What are the solutions to the equation x^2-13x+5=0 ?
The solutions to the equation x^2-13x+5=0 are x=(13+sqrt(149))/2 ,x=(13-sqrt(149))/2
Find the zeros of x^2-13x+5=0
The zeros of x^2-13x+5=0 are x=(13+sqrt(149))/2 ,x=(13-sqrt(149))/2