What are the solutions to the equation 5b^2+4b+4=0 ?

The solutions to the equation 5b^2+4b+4=0 are b=-2/5+i 4/5 ,b=-2/5-i 4/5

Find the zeros of 5b^2+4b+4=0

The zeros of 5b^2+4b+4=0 are b=-2/5+i 4/5 ,b=-2/5-i 4/5

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5 b^{2} + 4 b + 4 = 0

b = - \frac{2}{5} + i \frac{4}{5}, b = - \frac{2}{5} - i \frac{4}{5}

Solution steps

5 b^{2} + 4 b + 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

4^{2} - 4 \cdot 5 \cdot 4 : 8 i

b_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 5}

Separate the solutions

b_{1} = \frac{- 4 + 8 i}{2 \cdot 5}, b_{2} = \frac{- 4 - 8 i}{2 \cdot 5}

b = \frac{- 4 + 8 i}{2 \cdot 5} : - \frac{2}{5} + i \frac{4}{5}

b = \frac{- 4 - 8 i}{2 \cdot 5} : - \frac{2}{5} - i \frac{4}{5}

The solutions to the quadratic equation are:

b = - \frac{2}{5} + i \frac{4}{5}, b = - \frac{2}{5} - i \frac{4}{5}

\frac{1}{16} x^{2} + x + 4 = 0

x^{2} + 28 x

1 + 4 + 7 + 10 (3 n - 2) = \frac{n ( 3 n - 1 )}{2}

2 x (1 + x) = 4

4 k (k + 3) = - 15

What are the solutions to the equation 5b^2+4b+4=0 ?
The solutions to the equation 5b^2+4b+4=0 are b=-2/5+i 4/5 ,b=-2/5-i 4/5
Find the zeros of 5b^2+4b+4=0
The zeros of 5b^2+4b+4=0 are b=-2/5+i 4/5 ,b=-2/5-i 4/5